If the work required to stretch a spring 1 ft
Web29 nov. 2024 · The work done in stretching or compressing a spring is proportional to the square of the displacement.If we double the displacement, we do 4 times as much work. … WebSo, the work needed to stretch a spring from 60 cm to 74 cm is. A = A 3 - A 2 = 21025/4 - 5625/4 = 3850 J. Need a fast expert's response? Submit order. and get a quick answer …
If the work required to stretch a spring 1 ft
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Web29 jan. 2024 · 1.If the work required to stretch a spring 3 ft beyond its natural length is 15 ft-lb, how much work is needed to stretch it 27 in. beyond its natural length? 2.A spring … Web-Eighteen foot-pounds of work is required to stretch a spring 4 inches from its natural length. Find the work required to stretch the spring an additional 3 inches. Solutions Verified Solution A Solution B Reveal all steps Create an account to view solutions By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Web1f the work required to stretch a spring 1 ft beyond its natural... Image transcription text According to Hooke's Law, the force required to hold the spring stretched X m beyond its natural length is given by f (x) = kx, where k is the spring constant. Suppose that 2 J of work is needed to stretch a spring from its natur... Show more... Show more Web24 feb. 2024 · We can find k by using the given work and the integral for work: W = ∫F(x)dx from 0 to 1 ft; where W is the work required to stretch the spring 1 ft beyond its …
Web8 sep. 2024 · A force of 10 lb is required to hold a spring stretched 4in.beyond its natural length. How much work The Answer Key 16.3K subscribers Subscribe 2.5K views 2 years ago A force of 10 lb is... WebRecall Hooke's Law: The force required to maintain a spring stretched x units beyond its natural length is proportional to x. So f (x) = kx, where k is the spring If the work …
Web1.A spring has a natural length of 10 in. An 800-lb force stretches the spring to 14 in. (a)Find the force constant. Answer: Since 14 10 = 4 inches is 1 3 of a foot and since, by …
WebCompute the work required to stretch a spring from equilibrium to 9 cm past equilibrium, assuming that the spring constant is k =150 kg/s2. W = J. Solution: The work required … nothing but the truth newsWebTranscribed Image Text: If the work required to stretch a spring 1 ft beyond its natural length is 15 ft-lb, how much work is needed to stretch it 3 in. beyond its natural length? … how to set up finger scanner on dell laptopWebSolution for If the work required to stretch a spring 1 ft beyond its natural length is 9 ft-lb, how much work is needed to stretch it 9 in. beyond its natural… how to set up find my airpodsWebAnswer to: If the work required to stretch a spring 1 feet beyond its natural length is 12 feet-lb. How much work is needed to stretch it 9 inches... Log In. Sign Up. Menu. ... If … how to set up finger scanner on lenovoWeb23 okt. 2024 · The work required to stretch it 9 inches Given that : Work (W) = kx Take the integral of W at 3 fts beyond its natural length; W = ∫kx dx at 0 to 3 W = k ∫xdx at 0 to 3 W = 6 W = k [x²/2] at x =0 to x = 3 6 = k [3² /2] - 0 6 = k [9/2] 12 = 9k k = 12/9 = 4/3 = 1.333 Converting inches to feet: 1 inch 0.0833 ft 9 inches = 0.75 ft nothing but the truth peacockWebFormula Used. Spring work = Spring Constant* (Displacement at point 2^2-Displacement at point 1^2)/2. Wspring = Kspring* (x2^2-x1^2)/2. This formula uses 4 Variables. … nothing but the truth reaction paperWeb5 mei 2024 · Q: Suppose the work W_0 done when a spring is stretched 6 inches from its natural length is 1/2 ft-lb. Find the work W done in extending the spring 3 more inches. … how to set up find my phone on iphone 13